# C Programming Questions and Answers:: Floating Point Issues

### Exercise

"

#### If the binary eauivalent of 5.375 in normalised form is 0100 0000 1010 1100 0000 0000 0000 0000, what will be the output of the program (on intel machine)?

``````
#include
#include
int main()
{
float a=5.375;
char *p;
int i;
p = (char*)&a;
for(i=0; i<=3; i++)
printf("x\n", (unsigned char)p[i]);
return 0;
}
``````
 A. 40 AC 00 00 B. 04 CA 00 00 C 00 00 AC 40 D. 00 00 CA 04

#### Which statement will you add in the following program to work it correctly?

``````
#include
int main()
{
printf("%f\n", log(36.0));
return 0;
}
``````
 A. #include B. #include C #include D. #include

#### Which of the following statement obtains the remainder on dividing 5.5 by 1.3 ?

 A. rem = (5.5 % 1.3) B. rem = modf(5.5, 1.3) C rem = fmod(5.5, 1.3) D. -we can't divide

#### What will you do to treat the constant 3.14 as a float?

 A. use float(3.14f) B. use 3.14f C use f(3.14) D. use (f)(3.14)

#### The binary equivalent of 5.375 is

 A. 101.101110111 B. 101.011 C 101011 D. None of above

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