Aptitude:: Height and Distance

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Exercise

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An observer 1.6 m tall is 20√3 away from a tower. The angle of elevation from his eye to the top of the tower is 30ο. The heights of the tower is:

A. 21.6 m B. 23.2 m
C. 24.72 m D. None of these

Answer: Option A

Explanation:

 

Let AB be the observer and CD be the tower

Draw BE  CD.

Then, CE = AB = 1.6 m,

      BE = AC = 203 m.

CD = CE + DE = (1.6 + 20) m = 21.6 m.

 

 


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